**Question:**

In the expansion \({\left( {{\rm{0.2\; + \;0,8}}} \right)^{\rm{5}}}\), the fourth term is:

**Reference explanation:**

**Correct Answer: EASY**

The general term in the above expansion is

\({T_{k + 1}} = C_5^k. {\left( {0,2} \right)^{5 – k}}. {\left( {0,8} \right)^k} \)

So the fourth term is

\({T_4} = C_5^3. {\left( {0,2} \right)^2}. {\left( {0.8} \right)^3} = 0.2028\).

$\mathrm{}$ADSENSE

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