Question:
In the expansion \({\left( {{\rm{0.2\; + \;0,8}}} \right)^{\rm{5}}}\), the fourth term is:
Reference explanation:
Correct Answer: EASY
The general term in the above expansion is
\({T_{k + 1}} = C_5^k. {\left( {0,2} \right)^{5 – k}}. {\left( {0,8} \right)^k} \)
So the fourth term is
\({T_4} = C_5^3. {\left( {0,2} \right)^2}. {\left( {0.8} \right)^3} = 0.2028\).
ADSENSE
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