Solve Lesson 51 Page 89 SBT Math 10 – Kite>


Topic

In the coordinate plane Oxygenfor circle (C): (x − 3)2 + (y − 4)2 = 25. The tangent at the point M(0; 8) on the circle with a normal vector is:

A. \(\overrightarrow n = ( – 3;4)\) B. \(\overrightarrow n = (3;4)\) C. \(\overrightarrow n = (4; – 3)\) D. \ (\overrightarrow n = (4;3)\)

Solution method – See details

Suppose d is tangent at USA of the (OLD). Then \(IM \bot d\) (I is the center of (OLD)) Candlestick d get vector \(\overrightarrow {OM} \) as VTPT

Detailed explanation

(OLD) has a mind I(3; 4), radius CHEAP = 5

Suppose d is tangent at USA of the (OLD) \( \Rightarrow IM \bot d\) \( \Rightarrow \) d get \(\overrightarrow {IM} \) as VTPT

\( \Rightarrow \)\(\overrightarrow {IM} = ( – 3;4)\)

Choose A



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