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Topic
Write the round number of each of the following approximations:
a) -131 298 with precision \(d = 20\)
b) 0.02298 with precision \(d = 0.0006\)
Solution method – See details
We say \(a\) is an approximation of \(\overline a \) with precision \(d\) if \({\Delta _a} = \left| {a – \overline a } \right| \le d\)
Detailed explanation
a) -131 298 with precision \(d = 20\)
The largest row of precision \(d = 20\) is tens, so we round -131 298 to hundreds we get the rounded number of -131 298 which is -131 300
b) 0.02298 with precision \(d = 0.0006\)
The largest row of precision is \(d = 0.0006\) which is ten thousandths, so we round 0.02298 to thousandths we get 0.02298 rounding number 0.023
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